The Hall-effect sensors we have cannot handle the current needed to turn some of our 12-volt relays on. So, your task is to solve this problem using a transistor.

Using an ATS177 Hall-effect sensor, a PN3643 transistor, resistors, and a 50 ohm dummy load (to simulate a 50 ohm relay coil), design a circuit that will enable provide either 12 volts or 0 volts to the 50 ohm load, depending on the state of the Hall-effect sensor. (The Hall-effect sensor is the one we've used before.)

Calculate the power dissipation for the 50 ohm load. You'll find that power resistors will be needed to handle this wattage. We don't have any 50 ohm power resistors with a high enough power rating, so you'll need to put two 100 ohm power resistors in parallel. With two resistors in parallel, each one will dissipate half the total power.

Don't ruin the breadboard by shoving resistor leads into it that are two large in diameter. If you run into this problem, solder thinner wire onto the resistor leads.